Question

T 3 - 3t 2 find the velocity and acceleration at t =1sec

Answer 1

S = t³ + 3t² 
differentiating with respect to t
V = 3t² + 6t
Given t = 1 sec
So, V = 3+6 = 9 m/s

Differentiating v with respect to t
a = 6t+6 = 6+6 = 12 m/s²