Question

T^3-4t^2+5t-2 find zeros of this cubic equation. plzzz fast

Answer 1

Answer:

HERE IS YOUR ANSWER⬇

{t}^{3} - 2 {t}^{2} - 15t \\ \\ = t( {t}^{2} - 2t - 15) \\ \\ = t( {t}^{2} - 5t + 3t - 15) \\ \\ = t( \: t(t - 5) + 3(t - 5) \: ) \\ \\ = t(t - 5)(t + 3)

Hence, the zeroes of the cubic equation are

0, 5 and (-3).