Question

T(-3,6), R(9,-10) Find the distance between the following pairs of points.

Answer 1

Final Answer: 20 units 

Logic Used: 
1) Distance between points $A(x_{1},y_{1}) \:\:and\:\: B(x_{2},y_{2})$ is given by 

$\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

2)Here,
 A = (-3,6)
B=(9,-10)

$AB= \sqrt{(9+3)^{2}+(-10-6)^{2}} = \sqrt{400} = 20\:\: units$

Hence ,Required Distance is 20 units .

Answer 2

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Distance between two points

A(x1,y1) and B(x2,y2) is

AB = √( x2 - x1 )² + ( y2 - y1 )²

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Here ,

T( -3 , 6 ) = ( x1 , y1 ) ,

R( 9 , -10 ) = ( x2 , y2 ) ,

TR = √ [ 9 - ( -3 ) ]² + [ -10 - 6 ]²

= √ ( 9 + 3 )² + ( -16 )²

= √ 12² + 16²

= √ 144 + 256

= √400

= √ 20²

Therefore ,

TR = 20

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