Question

t^3+t^2+3t-1=0 where t = tan a

Answer 1

Answer:

0

Step-by-step explanation:

Given, x=3t2+1,y=t3−1

Slope of the tangent to the given curve is dxdy=dtdy×dxdt

=3t2×6t1

=2t

Since the slope has to be calculated at x=1, i.e. at 3t2+1=1, we get t=0

Thus, the required slope is 0.