Question

t^4-t^2=2, find the value of t.​

Answer 1

Answer:

The first term is, t4 its coefficient is 1 .

The middle term is, -t2 its coefficient is -1 .

The last term, "the constant", is -2

Step-1 : Multiply the coefficient of the first term by the constant 1 • -2 = -2

Step-2 : Find two factors of -2 whose sum equals the coefficient of the middle term, which is -1 .

-2 + 1 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 1

t4 - 2t2 + 1t2 - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

t2 • (t2-2)

Add up the last 2 terms, pulling out common factors :

1 • (t2-2)

Step-5 : Add up the four terms of step 4 :

(t2+1) • (t2-2)

Which is the desired factorization

Answer 2

Answer:

√2

Step-by-step explanation:

$\rm t^4-t^2=2$

$\rm t^4-t^2-2=0$

$\rm \Rightarrow (t^2 -2)(t^2+1) =0$

$\rm \Rightarrow t^2 -2=0$

$\rm \Rightarrow t=\sqrt{2}$