(t-4)(t+7)=0, standard form?
coefficients a, b, c?
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Answer:
(t-4)(t+7)=0
t²+7t-4t-28 =0
t² +3t -28=0
comparing t² +3t -28=0 with ax²+bx+c=0
a=1 , b = 3 and c= -28
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