Question

T
7. In the adjoining figure, find the area of PQR and
the height PS​

Answer 1

Answer:

As area of right angled triangle= 1/2(Base)(Height)

⇒ar(ΔPQR)=ar(QTR)−ar(PQT)=

= 1/2(QT)(TR)-1/2(QT)(PT)

=1/2(QT)(TR-PT)=1/2(QT)(PR)=

1/2(12)(15)=90cm sq

1/2(PS)(QR)=90

PS×20=180

PS=9cm