T. A 40 N force pulls a system of three masses on a horizontal frictionless surface as shown in the fig. Tension Ti is
1) 12N
2) 6N
3) 2N
4) 4N
with step by step problem
Answers
Answer:
From FDB of 3 blocks.
T
1
=10a ....(1)
T
2
−T
1
=20a ....(2)
60−T
2
=20a ....(3)
addingequation(1)+(2)
T
2
=30a (4)
from (3) and (4) equation
60=50a
a=
5
6
=m/s
2
now
T
1
=10a=
5
10×6
=12N
T
2
=30a=
5
30×6
=36N
solution
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SIMILAR QUESTIONS
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Three blocks of masses m
1
,m
2
and m
3
are connected to massless strings as shown on a frictionless table. They are pulled with a force T
3
=40N. If m
1
=10kg,m
2
=6kg and m
3
=4kg, the tension T
2
will be
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Two blocks A and B are connected by a massless string ( shown in figure) . A force of 30N is applied on block B . The distance travelled by centre of mass in 25 starting from rest is
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