T
å.
->
b and c are perpendicular to
ő + , è + à andă + 6
>
1
respectively and if
a + b
6, 1b + c = 8 and
>
है
ct a
= 10, then a + b + c
is equal to
Answers
Answered by
2
Answer:
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Step-by-step explanation:
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Answered by
1
Answer
∵a⊥(b+c)
∴a.(b+c)=0⇒a.b+a.c=0 ...(1)
Similarly b⊥(c+a)⇒b.c+b.a=0 ...(2)
and c⊥(a+b)=0⇒c.a+c.b=0 ...(3)
Adding (1),(2),(3), we get
2(a.b+b.c+c.a)=0
Now, (a+b+c)
2
=a
2
+b
2
+c
2
+2(a.b+b.c+c.a)
=∣a∣
2
+∣b∣
2
+∣c∣
2
+0=3
2
+4
2
+c
2
=50
Hence ∣a+b+c∣=
∵a⊥(b+c)
∴a.(b+c)=0⇒a.b+a.c=0 ...(1)
Similarly b⊥(c+a)⇒b.c+b.a=0 ...(2)
and c⊥(a+b)=0⇒c.a+c.b=0 ...(3)
Adding (1),(2),(3), we get
2(a.b+b.c+c.a)=0
Now, (a+b+c)
2
=a
2
+b
2
+c
2
+2(a.b+b.c+c.a)
=∣a∣
2
+∣b∣
2
+∣c∣
2
+0=3
2
+4
2
+c
2
=50
Hence ∣a+b+c∣=
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