Question

T & AIIMS
If a wire is stretched by 2%, then find the energy
stored in the wire per unit volume (in J/m3)
(Y = 4 * 108 N/m2)
(1) 4 x 104
(2) 8 x 104
-3) 12 × 104 one (4) 16 x 104
The length of wire is increased hun 30% Find the​

Answer 1

Explanation:

option 2 is correct

strain =dl/l = 2/100 = 0.02

energy stored/volume =

(1/2 * strain^2)*(Y)

= 0.5*0.02^2*(4*10^8)

= 80000 J/m^3 = 8*10^4 J/m^3