Question

t can take 12 hours to fill the swimming pool using 2 pipes. if the pipe of larger diameter is used for 4 hours and the pipe of smaller diameter is used for 9 hours, only half of the pool can be filled. how long would it take for each pipe to fill the tank separately
pls experts answer this one

Answer 1

hope so it will help u a lot.......
the solution would be like this:-

let the time taken by the 1 pipe be x hours and let the time taken by the 2 pipe be y hours.

& the in 1 hour the 1 pipe can fill it=1/x

the in 1 hour the 2 pipe can fill it=1/y

1/x +1/y = 1/12 -1

4/x = 9/9 =1/2 -2

let 1/x be a and 1/y be b.

a+b= 1/12 -3

4a + 9b = 1/2 -4

multiply 3 by 4 and then subtract 5 and 6.

4a +4b=1/3 -5

4a + 9b = 1/2 -6

we get, b=1/30

y=30.

sustituting the value of y in eq. 3

a+1/30=1/12

x=20.

Hence the 1st pipe would take 20hours and the 2nd pipe would take 30 hours.

Answer 2

Answer:

here 1/x=a and 1/y = b so pipe of smaller diameter takes 30 hrs and larger will take 20 hrs to fill the tabk separately