Question

T is a two-digit number whose units digit is non-zero.
T is greater than twice the number formed by
interchanging the positions of its digits. How many
values can T take?​

Answer 1

Let the number is ab so

10a+b >3(10b+a)

7a>29b

a/b>29/7

So the possible pair of (a,b) are (5,1), (6,1), (7,1) , (8,1) , (9,1) & (9,2)

Thus total 6 such numbers are possible.