Question

T = L^1/2 g^-1/2 = ?????

Solve it and explain it please.​

Answer 1

Answer:

The given is a dimension equation for time period of a simple pendulum of length L

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Answer 2

Answer:

$2 \sqrt{3} \times 2 \sqrt{3} \\ = 2 \times 2 \times \sqrt{3} \times \sqrt{3} \\ = 4 \times 3 \\ = 12$

hope it's help to you