T o m + n a g ---------- g o a t ----------if m=6, what is the value of g + o + n + t?
Answers
Step-by-step explanation:
T (7) O (0) M (6)
(+) N (3) A (4/5/6/9) G (1)
---------------------------------------------------------
G (1) O (0) A (4/5/6/9) T (7)
-----------------------------------------------------------
G+O+N+T = 1+0+3+7=11
*Note: Value of A can't be determined
Answer:
The value of (g + o + n + t) = (1 + 0 + 3 + 7) = 11
Step-by-step explanation:
Since the condition of M =6 is given, We can start putting values of each number.
1. m+g = 6+1 = 7
(since the highest possible value of G is 1 because the sum of two unit digits will never have a sum greater than 18)
2. Similarly We get all the values of the alphabet this way.
Therefore, the other values are as follows,
T = 7, O = 0, M = 6, N = 3, A = 2, G = 1.
Now, Put all the values in the condition i.e, T o m + n a g = g o a t
= 7 0 6 + 3 2 1 = 1 0 2 7
Both LHS =RHS, hence condition is Satisfied.
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