Question

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Solve the problems given below :
1. In a two-digit number, the ones digit is 3 times
the tens digit. If 10 is added to the 2 times of
the number, its digits interchagne their places
in the new number. Find the number.​

Answer 1

Answer:

Step-by-step explanation:

Let the 2 digit no. be =10x + y

where y is the unit place digit and x is the tens place digit.

So it's reverse will be = 10y+x

ATQ

y = 3x

2(10x +y) +10 = 10y + x

put y = 3x in the above equation

2(10x + 3x) + 10 = 10*3x + x

26x + 10 = 31x

5x = 10

x=2

y = 3x =6

therefore the no is 10x +y = 20+6 =26