Question

T ree particles A.B and C are thrown from the top of a tower with the same speed. A is thrown up, B is
own down and C is horizontally. They hit the ground with speeds VV, and V respectively then
V, <V, <V
b) V = V.>V
c) V =V=VC
d) V >V=VC
​

Answer 1

Answer:

d v=v.)v....

...........

Answer 2

(c)

For A: it goes with velocity u will reach its maximum height(i.e velocity becomes zero) and comes back to O and attain velocity u.

Using v2 =u 2 +2as⇒v

A = √u2+2gh

For B: going down with velocity u:

v B = √u 2 +2gh

For C: horizontal velocity remains same i.e u.Vertical velocity v y = √0+2gh =√2gh

The resultant, v c =√ v x2 +v y2=√u2+2gh

Hence, v A =v B =v C