Question

t=root x+10 here x is displacement and t is time ,find out the accerlartion ​

Answer 1

Answer:

$a = 2t - 20$

Explanation:

$t = \sqrt{x} + 10\\\sqrt {x} = t - 10\\x = t^2 + 100 - 20t$

This can be written as a function of time,

$g(t) = t^2 + 100 - 20t$

which returns the displacement given an instance of time ( t ).

Now, we know,

$a = \frac{\Delta v}{\Delta t}$

Calculating the derivative of g( t ),

$\frac{d}{d t} g(t) = 2t - 20$

which could be written as,

$g'(t) = 2t - 20$

This function will be return the acceleration given time t.