Question

T
S
R
2) In the Fig. a rectangle PQRS is inscribed in a circle with
P
centre T. Complete the following activity to
Prove arc PQ arc SR
arc SPQ = arc PQR
arc SPQ = arc PQR
PQRS is rectangle
chord PQ chord
(opposite side of rectangle)
arc PQ arc
(arcs corresponding to congruent chords)
chord PS chord QR
(opposite side of rectangle)
arc SP = arc
(arcs corresponding to congruent chords)
Measures of arcs SP and QR are equal.
Now m (arc SP) + m (arc PQ) = + m (arc QR)
m (arc SPQ) =
arc SPQA​

Answer 1

Step-by-step explanation:

Correct option is A)

Given rectangle PQRS iscribed in aquadrant of a circle , with P at the centre and R on the circumference .And PS=12 cm and QP=5 cm.

In rightangle ΔPQR

(PR)

2

=(QP)

2

+(QR)

2

=(12)

2

+(5)

2

=144+25=169

⇒PR=13cm

The PR is the redius of circle

Then diameter =2×12=26cm

solution