Question

T square minus 3into root5 upon 2 into t minus 5

Answer 1

Answer:

Step-by-step explanation:

$t^{2} - \frac{3\sqrt{5t} }{2} - 5 = 0\\\\\frac{2t^{2} - 3\sqrt{5t} - 10}{2} = 0\\\\2t^{2} - 3\sqrt{5t} - 10 = 0\\\\a = 2\\ b = - 3\sqrt{5} \\c = -10\\\\\frac{- b +- \sqrt{b^{2} - 4ac} }{2a} =t \\\\\\\frac{3\sqrt{5} +- \sqrt{ 45 + 80} }{4} =t\\\\\frac{3\sqrt{5} +- \sqrt{ 125} }{4} =t \\\\\frac{3\sqrt{5} +- 5\sqrt{ 5 } }{4} =t\\\\=> \frac{3\sqrt{5} + 5\sqrt{ 5} }{4} =t\\\\=>\frac{8\sqrt{ 5} }{4} = t\\\\=>2\sqrt{ 5} = t\\\\ Also \\\frac{3\sqrt{5} - 5\sqrt{ 5}}{4} = t\\\\\frac{-2\sqrt{5} }{4} = t$

$\frac{-\sqrt{5} }{2} = t$