Question

ɧεгε ıร tɧε զนεรtıσŋ ✌

_______________________

● 1. Which of the following polynomial has -3 as a zero ?
(a) (x-3)
(b)x^2-9
(C) x^2-3x
(d) x^2+3

_______________________​

Answer 1

Answer:

$option \: \: \: b ) \: \: \: is \: correct$

Step-by-step explanation:

when we put zero in the equation we get our ans is zero.

hence ,put x=3 one by one in

each.

For option A)

$= > - 3 - 3 = \: - 6$

Option A) is incorrect

for option B)

${ - 3}^{2} - 9 = 9 - 9 = 0$

option B) is correct.

for option C)

${ - 3}^{2} - 3( - 3) = 9 + 9 = 18$

option C) is incorrect.

for option D)

${ - 3}^{2} + 3 = 9 + 3 = 12$

option D) is also incorrect.

hope it helps you.

Yo❤️.

Answer 2

option (b)✔✔

when we put zero in the equation we get our ans is zero.

hence ,put x=3 one by one in

each.

For option A)

= > - 3 - 3 = \: - 6=>−3−3=−6

Option A) is incorrect

for option B)

${ - 3}^{2}$- 9 = 9 - 9 = 0−32−9=9−9=0

option B) is correct.

for option C)

${ - 3}^{2}$ - 3( - 3) = 9 + 9 = 18−32−3(−3)=9+9=18

option C) is incorrect.

for option D)

${ - 3}^{2}$+ 3 = 9 + 3 = 12−32+3=9+3=12

option D) is also incorrect.

hope it helps you.