Question

T the age of a boy is double the age of his brother after 4 years product of their ages will be 160 find their present age

The age of a boy is double the age of his brother after 4 years the product of their ages will be 160 find their present age

Answer 1

Answer:

Boy is 12 and brother is 6

Step-by-step explanation:

x = boy's age

y = brother's age

ATQ,

(x + 4)(y + 4) = 160

But, x = 2y ....given

(2y + 4)(y + 4) = 160

On simplifying,

y^2 + 6y - 72 = 0

(y - 12)(y + 6) = 0

y = 12 as y = -6 is not admissible.

x = 2y

x = 6

Boy is 12, brother is 6.

verify

12 = 2x6 ✓

(12+4)*(6+4) = 16x10 = 160 ✓

Answer 2

Answer:

boy's age is 12 yrs and brother's age is 6 yrs.

Step-by-step explanation:

x = boy's age

y = brother's age

ATQ,

(x + 4)(y + 4) = 160

But, x = 2y ....given

(2y + 4)(y + 4) = 160

On simplifying,

y^2 + 6y - 72 = 0

(y - 12)(y + 6) = 0

y = 12 as y = -6 is not admissible.

x = 2y

x = 6

Boy is 12, brother is 6.

verify

12 = 2x6 ✓

(12+4)*(6+4) = 16x10 = 160 ✓