Chemistry, asked by thumumadhavi777, 6 months ago

T. The mass
Olmde 500 ml
of ab, log required to prepare
s. sg]
solution is​

Answers

Answered by Anonymous
8

Explanation:

1000 mL will weigh 1800g

mass of H2SO4

present = 1800 gm

number of mole of H2SO4

= actual mass/molarmass= 1800 ÷ 98 = 18.36

thus molarity of a stock solution is 18.36 M

To prepare 500 mL of 0. 9 M solution, M1 V1

=M2V2

=> 18.36 x A = 0.9 x 500 mL

=> 450/18.36

= 24.5 ml

√\_________Anushka❤❤

Answered by teresasingh521
1

Answer:

  • 24.5....
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