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Using identity the product of (3m+2)(3m+5)
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0
Answer:
We need to multiply the polynomials (2l−3m)(2l+3m)
By using identity (a+b)(a−b)=a
2
−b
2
, we can find the product.
Here a=2l,b=3m
Therefore, (2l−3m)(2l+3m)=4l
2
−9m
2
This is the required answer.
Answered by
1
3m(3m+5)+2(3m+5)
=9m2+15m+6m+10
=9m2+21m+10
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