t1=12 t2=14 t3=16 ........398 find t23th term
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Step-by-step explanation:
Her t1 = ist term. T2 denote 2 term and so on. So according to formula to find n term = L = a +(n-1)d . Here L is last term. 398= 12+(n-1)2. 398-12/2 =n-1. , 194. = n then t23.= a+(23-1 )2 = 12+22*2 = 12+44 = 56. Answer
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