Question

t1=50+_0.4
t2=30+_0 .3
Calculate sum and difference in error t

Answer 1

t1 = 50±0.4

t2 = 30±0.3

Error in sum of t

= (50+30)±(0.4+0.3)

=80±0.7

Error in difference of t

= (50-30)±(0.4+0.3)

=20±0.7

Cheers!