t1=5and t2=9 then find s200 in ap
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100(10+199*4) just solve this
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Term 1 = 5 = a
Term 2. = 9
Common difference = t2 - t1 = 9-5 = 4
S200 = n/2[2a + (n -1)d] = 200/2 [2 × 5 + (200 - 1)4]
S200 = 100[10 + 199 × 4] = 100 × 806
Ans. S200 = 80600
^__^...
Term 2. = 9
Common difference = t2 - t1 = 9-5 = 4
S200 = n/2[2a + (n -1)d] = 200/2 [2 × 5 + (200 - 1)4]
S200 = 100[10 + 199 × 4] = 100 × 806
Ans. S200 = 80600
^__^...
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