Question

t10 -t5 =200(Ans:-40)find common difference​

Answer 1

Answer:

$\large\boxed{\sf{40}}$

Step-by-step explanation:

We know that, for an AP

tn = a + (n-1)d

Where,

• tn = nth term
• a = first term
• d = common difference

Therefore, we have,

=> t10 = a + (10-1)d

=> t10 = a + 9d

And , similarly, we have,

=> t5 = a + (5-1)d

=> t5 = a + 4d

Now, From the question, we have,

=> t10 - t5 = 200

=> a + 9d - (a +4d ) = 200

=> a + 9d - a - 4d = 200

=> 5d = 200

=> d = 200/5

=> d = 40

Hence, the common difference is 40.