t10-t5=200 find. common difference
Answers
Answer: 40
Step-by-step explanation:
We know that, for an AP
tn = a + (n-1)d
Where,
tn = nth term
a = first term
d = common difference
Therefore, we have,
=> t10 = a + (10-1)d
=> t10 = a + 9d
And , similarly, we have,
=> t5 = a + (5-1)d
=> t5 = a + 4d
Now, From the question, we have,
=> t10 - t5 = 200
=> a + 9d - (a +4d ) = 200
=> a + 9d - a - 4d = 200
=> 5d = 200
=> d = 200/5
=> d = 40
Hence, the common difference is 40.
40
We know that, for an AP
tn = a + (n -1)d
Where,
tn = nth term
a = first term
d = common difference
Therefore, we have,
=> t10 = a + (10-1)d
=> t10 = a + 9d
And , similarly, we have,
=> t5 = a + (5-1)d
=> t5 = a + 4d
Now, From the question, we have,
=> t10 - t5 = 200
=> a + 9d - (a +4d ) = 200
=> a + 9d - a - 4d = 200
=> 5d = 200
=> d = 200/5
=> d = 40
Hence, the common difference is 40.