Question

t12 for the AP. 12, 9,6..​

Answer 1

Answer:

12th term of this A.P. is -21

Step-by-step explanation:

Given :

we are given a A.P.

12 , 9 , 6 ....

To Find :

12th term of this A.P.

Solution:

Since the given A.P. is 12 , 9 , 6 ...

Observing the given A.P. we get to know that the first term of this A. P. = 12

and the common difference d = 9 - 12 = - 3

Since we know that the nth term of an A.P is given by = $a+(n-1)d$

where d is the common difference and a is the first term

so substituting these value from the Given A.P. we get

12th term of the given A.P. is  = $a+(n-1)d$

                                                 $= 12+(12-1)(-3)$

                                                 $=12+(11)(-3)$

                                                 $= -21$

Hence we get that 12th term of this A.P. is -21

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Answer 2

The 12th term for the A.P. is -21

Step-by-step explanation:

Given:

The series in A.P. is 12, 9, 6, .....

To find:

t12 for the A.P.

Solution:

The series is in A.P.

The first term is 12

∴ a = 12

Now, the difference between the terms = d

= 9-12

= -3

∴ d = -3

We are required to find the 12th term

By the formula

$t_{n} = a+ (n-1)d$

here, n = 12, a = 12, d = -3

Putting the values

$t_{12}$ = 12 + (12-1)(-3)

∴ $t_{12}$ = 12 + 11(-3)

∴ $t_{12}$ = 12+(-33)

∴ $t_{12}$ = -21

∴ t12 for the given A.P. is -21

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