t12of the series 0.04,0.2,1 ....is
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1
Answer:
1943125.
Step-by-step explanation:
It is a GEOMETIRIC PROGRESSION.
a=0.04,r=5,n=12
nth term in geometric progression is a(r)^n-1.
t12=0.04(5)^11= 1943125.
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