Question

t2+11t+24 factorise ​

Answer 1

Factoring  t2-11t+24  

The first term is,  t2  its coefficient is  1 .

The middle term is,  -11t  its coefficient is  -11 .

The last term, "the constant", is  +24  

Step-1 : Multiply the coefficient of the first term by the constant   1 • 24 = 24  

Step-2 : Find two factors of  24  whose sum equals the coefficient of the middle term, which is   -11 .

     -24    +    -1    =    -25  

     -12    +    -2    =    -14  

     -8    +    -3    =    -11    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -8  and  -3  

                    t2 - 8t - 3t - 24

Step-4 : Add up the first 2 terms, pulling out like factors :

                   t • (t-8)

             Add up the last 2 terms, pulling out common factors :

                   3 • (t-8)

Step-5 : Add up the four terms of step 4 :

                   (t-3)  •  (t-8)

            Which is the desired factorization

Final result :

 (t - 3) • (t - 8)

Answer 2

Answer:

I hope this will help you :)