t2-3t=4-2t solve in general form
Answers
Answer:
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(t-(3/4))2 is
(t-(3/4))2/2 =
(t-(3/4))1 =
t-(3/4)
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
t-(3/4) = √ -23/16
Add 3/4 to both sides to obtain:
t = 3/4 + √ -23/16
In Math, i is called the imaginary unit. It satisfies i2 =-1. Both i and -i are the square roots of -1
Since a square root has two values, one positive and the other negative
t2 - (3/2)t + 2 = 0
has two solutions:
t = 3/4 + √ 23/16 • i
or
t = 3/4 - √ 23/16 • i
Note that √ 23/16 can be written as
√ 23 / √ 16 which is √ 23 / 4
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving 2t2-3t+4 = 0 by the Quadratic Formula .
According to the Quadratic Formula, t , the solution for At2+Bt+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
t = ————————
2A
In our case, A = 2
B = -3
C = 4
Accordingly, B2 - 4AC =
9 - 32 =
-23
Applying the quadratic formula :
3 ± √ -23
t = —————
4
Answer:
t = 4 is the correct answer
Step-by-step explanation:
2t-3t=4-2t
2t+2t-3t=4
4t-3t=4
t = 4
