Question

(t² - t - 4 ) = p(x) find zeros​

Answer 1

Answer:

$= > {t}^{2} - t - 4 = 0 \\ = > {t}^{2} - (2 - 2) t- 4 = 0 \\ = > {t}^{2} - 2 t+ 2t - 4 = 0 \\ = > t(t- 2) + 2(t - 2) = 0 \\ = > (t- 2)(t + 2) = 0 \\ t = 2 \: or \: t = - 2$

zeroes are 2 and -2

Answer 2

Step-by-step explanation:

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