Math, asked by gourang96521, 1 year ago

t³-12t²+32t what is the value of t

Answers

Answered by Anonymous

0

Answer:

t^3 -12t^2 +32t

t( t^2 -12t +32)

t( t^2 -8t -4t +32)

t( t( t-8) -4(t-8))

t( t-4)( t-8)

t= 0,4,8

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