Question

t3=17,t7=37 then find S10​

Answer 1

Answer:

A. P

T3=17=a+2d---1

T7=37=a+6d---2

Therefore, from eq. 1

a=17-2d

Put value of a in eq. 2

We get,

37=17-2d+6d

20=4d

d=5

Putting the value of d in value of a

ie a=17-2d=17-10=7

Sum of 10 terms will be

n/2(2a+(n-1)d)

=10/2(2*7+(10-1)5)

=5(14+(9*5))

=5(14+45)

=5*59

=295 Ans

Answer 2

Answer:

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