t3=t7=6 t3*t7=8 find a and d of an ap
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Answer :
t3= a+2d
t7= a+6d
t3+ t7 = 6
⇒a+2d+a+6d = 6
⇒2a+ 8d =6
⇒a = 6-8d / 2
⇒a= 3- 4d ---------------(i)
Now,
(a+2d)(a+ 6d) = 8
⇒a² +6da +2da +12d²=8
apply (i),
(3-4d)² + 8d (3-4d)+ 12 d²=8
⇒9+16d²_24d+24d-32d²+12d²=8
⇒-4d² +9 =8
⇒-4d²= -1
⇒d²= 1/4
⇒d=1/2 ---------------(ii)
Apply (ii) in (i):-
a= 3-4d
⇒a=3- 4× 1/2
⇒a =1
Step-by-step explanation:
@Genius
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