Math, asked by shaktipad, 1 year ago

t4 tan 60° sec 30° + (sin 31° sec 59° + cot 59° cot 31°/ 8sin²30°-tan²45°
Can you Answer it?

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Answered by smore0344
10

Answer:0


Step-by-step explanation:

[sec41°sin49°+cos29°cosec61°-2/√3(tan20°tan60°tan70°)]/[3(sin²31°+sin²59°)]

=[sec41°sin(90°-41°)+cos29°cosec(90°-29°)-2/√3{tan20°×√3×tan(90°-20°)}]/

[3{sin²31°+sin²(90°-31°)]

=[sec41°cos41°+cos29°sec29°-2(tan20°cot20°)]/[3(sin²31°+cos²31°]

=(1+1-2)/(3×1)

=0


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