T6=19, T17=41 then T40=?
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Answered by
1
Answer:
T
n
=a+(n−1)d
Where a is the first term, d is the common difference and T
n
denotes the n-th term of an AP.
Given:
19=a+5d
41=a+16d
Solving the above equations gives: d=2,a=9
Therefore, T
40
=9+39⋅2=
87
Step-by-step explanation:
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Answered by
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