Question

T7:t3is equal to 13:5 find an ap

Answer 1

Answer:

$\frac{t7}{t3} = \frac{13}{5} \\ = \frac{a + 6d}{a + 2d} = \frac{13}{5} \\ 5(a + 6d) = 13(a + 2d) \\ 5a + 30d = 13a + 26 \\ 4d = 8a \\ d = 2a = value \: of \: d \: \\ put \: the \: value \: of \: d \: in \: equation \\ \frac{a + 6(2a)}{a + 2(2a)} = \frac{13}{5} \\ \frac{13a}{5a} = \frac{13}{5} \\ a = 1 = value \: of \: a \: \\ put \: a = 1 \: in \: equation \\ d = 2(1) \\ d = 2 = value \: of \: d$

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