Question

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TA
A conventional clock with numbers from 1 to 12 in order is cut into 3 pieces such that the sum of
numbers on each piece are in arithmetic progression (A.P.) with a common difference of 1. What is
the product of all numbers in the group in which 12 is present?
212
252
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264
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1
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None of these
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Answer 1

264 the product of all numbers in the group in which 12 is present if A conventional clock with numbers from 1 to 12 is cut into 3 pieces

Step-by-step explanation:

A conventional clock with numbers from 1 to 12

=> Total = 12 * 13/2 = 78

is cut into 3 pieces such that the sum of numbers on each piece are in arithmetic progression (A.P.)  with a common difference of 1

Let say sums are S - 1 , S , S + 1

S - 1 + S + S + 1 = 78

=> S = 26

Sum are 25  , 26  , 27

having 12 Can have

9 , 10 , 11 , 12  

10 , 11 , 12 , 1

11  , 12 , 1 , 2

12 , 1 , 2 , 3

11 + 12 + 1 +2 = 26   only satisfies

11 * 12 * 1 * 2 = 264

264 the product of all numbers in the group in which 12 is present

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