Question

TA
ABC is cyclic querdilateral
prove that
sin A + SinB = SinB+ sinc​

Answer 1

Answer:

In a cyclic quadrilateral, sum of opposite angles is 180.

So, A+C=180⇒C=180−A⇒sinC=sin(180−A)=sinA

B+D=180⇒D=180−B⇒sinD=sin(180−B)=sinB

So,

sinA+sinB−sinC−sinD

=sinA+sinB−sinA−sinB

=0

hope it help