Question

t• If sum of squares of number is 80 and difference of squares of number is 36 than what is the product of numbers

Answer 1

let the two numbers be x & y 
now make the equation for it
x^2 + 0xy + y^2 = 80(i)
x^2 - 2xy + y^2 = 36(ii)
Subtraction eliminates,  both x^2 and y^2 "The Sum of the square of two numbers is 80"
x^2 + y^2 = 80
" and the square of their difference is 36."
(x - y)^2 = 36
x^2 - 2xy + y^2 = 36
Use elimination, subtract from the 1st equation
x^2 + 0xy + y^2 = 80
x^2 - 2xy + y^2 = 36
Subtraction eliminates, both x^2 and y^2
2xy = 44
Divide both sides by 2
xy = 22So,the product of two numbers is: 22

i hope it will help you