Question

तीन लगातार पूर्णाकों का योग 21 है तो तीनों पूर्णाक ज्ञात काज।​

Answer 1

Answer:

1st number = 6

2nd number = 7

3rd number = 8

Explanation:

Let the 1st number be x

2nd number be x+1

3rd number be x+2

now, x+x+1+x+2=21

or 3x+3=21

or 3x=21-3

or 3x=18

or x= 18/3

or x=6

so 1st number = x = 6

2nd number= x+1 = 6+1 = 7

3rd number= x+2 = 6+2 = 8

Answer 2

The numbers are 8, 9, 10

GIVEN

Sum of three consecutive numbers = 21

TO FIND

Value of the numbers

SOLUTION

The above problem can be simply solved as follows;

let the numbers be, (x), (x+1) and (x+2)

According to the question

x + x + 1 + x + 2 = 21

Solving the equation

3x + 3 = 21

x + 1 = 7

x = 8

Hence, The numbers are 8, 9, 10

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