Science, asked by babanayak3110, 3 months ago

तीन संधारित्र जिनकी धारिताएँ क्रमश: 4 uF, 6 uF तथा 12 uF हैं, श्रेणीक्रम में जोड़े
गए हैं, तो संयोजन की तुल्य धारिता ज्ञात कीजिए।
Tond 12 UE​

Answers

Answered by Anonymous
14

Answer:

2 micro farad

Explanation:

जब भी संधारित्र श्रेणी क्रम है जुड़े हो तो उनका सयोजन तुल्य कुछ इस प्रकार से ज्ञात करते है..

1/c =1/c1+1/c2 + जितने भी संधारित्र हो

यह तीन है 4,6,12

तो

1/c =6/24+4/24+2/24=12/24=1/2

c=2

Answered by pulakmath007
1

SOLUTION

GIVEN

Three capacitors whose capacitances are 4 μF , 6 μF and 12 μF respectively, are added in series

TO DETERMINE

The equivalent capacitance of the combination.

EVALUATION

Here it is given that three capacitors whose capacitances are 4 μF , 6 μF and 12 μF respectively, are added in series

So by the given

 \sf{C_1 = 4 \: \mu F \: , \: C_2 = 6 \: \mu F \: , \: C_3 = 12 \: \mu F,}

Let the equivalent capacitance of the combination = C

Thus we have

\displaystyle\sf{ \frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} }

\displaystyle\sf{ \implies \: \frac{1}{C} = \frac{1}{4} + \frac{1}{6} + \frac{1}{12} }

\displaystyle\sf{ \implies \: \frac{1}{C} = \frac{3 + 2 + 1}{12} }

\displaystyle\sf{ \implies \: \frac{1}{C} = \frac{6}{12} }

\displaystyle\sf{ \implies \: \frac{1}{C} = \frac{1}{2} }

\displaystyle\sf{ \implies \: C = 2 }

FINAL ANSWER

The equivalent capacitance of the combination = 2 μF

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