Question

टेन थीटा = ग्यारह Anya Sabhi trikonmiti anupat gyat Karen​

Answer 1

Answer:

sin thita-p/h,tan thita-p/b, cot thita-b/p,cos thita -b/h,sec thita-h/b, cosec thita -h/p

given =tan thita =11(p/b) .so from given weknow that p=11 and b=1.and h( hypotenuse)=√p^2+b^2

Step-by-step explanation:

now we get h=√12 an d put them in above formula to get your answer