Question

त्रिकोण ABC मध्ये, कोनB=90⁰ , रेख BD ही मध्यगा आहे जर AB=3,BC=4,तर BD किती?​

Answer 1

Answer:

The answer is :- 5 cm

Step-by-step explanation:

According to the question,

the triangle ABC is a right-angled triangle.

Given,

AB = 3 cm

BC = 4cm

BD = x cm

{x}^{2} = {3}^{2} + {4}^{2}

{x}^{2} = 9 + 16

{x}^{2} = 25

x = {4 \sqrt{25} }^{2}

.°. x = 5 cm

Therefore, BD = 5 cm

Hope it helps you!!