Question

टू साइड्स आफ ए पैरेललोग्राम are 10 सेंटीमीटर एंड 7 सेंटीमीटर one of its diagonal is 13 cm फाइंड द एरिया​

Answer 1

Answer:

Step-by-step explanation:

Given, AB=12 cm, BC=10 cm

BD is the diagonal of parallelogram ABCD.

Also BD=16 cm

We know, △ABD≅△DCB     [S−S−S Congruence]

Also, area of parallelogram ABCD = Area of △ABD + Area of △DCB

                                            = 2 × Area of △ABD

                                            = 2  

s(s−12)(s−10)(s−16)

​

 

s=  

2

12+10+16

​

 

  = 19

Therefore, area of parallelogram ABCD= 2  

19(19−12)(19−10)(19−16)

​

 

                                           = 2  

3591

​

 

                                           = 2(59.92)

                                           = 119.8 cm  

2

 

Also, h is the distance of the two shorter sides.

We know, area of parallelogram = base×height

                                   = BC×h

Therefore, h=  

BC

Area of parallelogram ABCD

​

 

⇒h=  

10

119.8

​

 

⇒h=11.98 cm

Answer 2

Answer:

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