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Answers
Explanation:
Let PQ be the pole and the peacock is sitting at the top P of the pole. Let the hole be at Q. Initially, the snake is at
S
when the peacock notices the snake such that
QS=
27m
Suppose
v
m/sec is the common speed of both the snake and the peacock and the peacock catches the snake after
t
seconds at point
T
. clearly distance travelled by the snake in
t
seconds is same as the distance flown by peacock
∴
PT=
ST=
x
Thus, in right triangle
PQT
, we have
QT=
27−
x,PT=
x
and
PQ=
9
Using Pythagoras theorem, we have
PT 2
PQ 2
QT 2
x 2
9 2
(27−x) 2
⇒
x 2
81+
729−
54x+
x 2
0=
810−
54x⇒
54x=
810⇒
x=
15
∴
QT=
SQ−
ST=
(27−
15)m=
12m
Hence the snake is caught at a distance of
12m
from the hole
Answer:
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Explanation: