Question

Tahir and mamata are working in a project in TCS. Tahir being a problem solver came up with an interesting problem for his friend mamata
problem consists of a string of length N contains only case alphabets
It will be followed by Q queries, in which each query will contain an integer P(1<=P<=N) denoting a position within the string​

Answer 1

class solve

{

public static void main(String args[])

{

Scanner sc= new Scanner(System . in);

int arr [ ];

System . out . println("Enter the length of string");

int len=sc . nextInt();

arr =new int [ len ];

System . out . println("Enter the string");

string str=sc . next();

System . out . println("Enter number of queries to be made");

int q=sc . nextInt();

for ( int i = 0; i< q; i++)

{

int count =0;

System . out . println( "Enter the query" );

int p=sc . nextInt();

for (int j=0; j<p-1 ; j++)

{  

if( str . charAt ( j ) = = str . charAt ( p-1 ) )

{

count + + ;

}

}

arr [ i ] = count;

}

for ( int i= 0; i< q; i++)

{

System .  out .  println (arr [ i ]);

}

}

}

Answer 2

Python program to "Similar Char Problem".

Language used : Python Programming

Program :

n=int(input("enter string length :"))

stri=list(str(input("Enter the string :"))[:n])

nq=int(input("Enter the number of queries :"))

for i in range(nq):

  count=0

  q= int(input("Enter query :"))

  alpha = stri[q-1]

  for j in range(0,q-1):

      if alpha==stri[j]:

          count=count+1

  print("count is :",count)

Input :

enter string length :9

Enter the string :abacsddaa

Enter the number of queries :2

Enter query :9

Enter query :3

Output :

count is : 3

count is : 1

Explanation :

• Firstly, take the string length to be inputted from the user.

• Take string as an input from the user of the specified length mentioned, and list the elements in the string.

• Ask user about the number of queries he is going to perform.

• Run a loop ranging the number of queries to be made, and on entering the loop, ask user to input the query.

• Now, write an inner for loop ranging from 0 to the query -1 index.

• Now, check the value present in the given queryindex with the one's before them and keep on incrementing the count every time the same element found.

• Once done, come out of the innerloop andd print the count, and then, go for next query, if asked.

• Keep on repeating the same process until all the queries are done, outer loop terminates. That's it!

NOTE :

If you don't want descriptive statements in the input and outputs, delete them from the corresponding statements in the code.

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