Question

tahir travels twice as far as ahmed, but only one third as fast. ahmed starts at point x at noon on Monday and travels to point z, 300 km away, by 9:00 PM the same day. if Tahir starts 3 hrs later than ahmed, when will Tahir reach point z? ( assuming no stops were made)​

Answer 1

Answer:

tahir travels twice as far as ahmed,

Distance travelled by tahir = 2*distance by Ahmed

but only one third as fast.

Speed of tahir = 1/3* speed of Ahmed

ahmed starts at point x at noon on Monday and travels to point z, 300 km away, by 9:00 PM the same day.

Time taken by Ahmed = 9 hours.

Distance = 300

Speed = 300/9 = 100/9 km/hr

Tahir starts 3 hrs later than ahmed, when will Tahir reach point z?

Speed of tahir = 1/3*100/9 = 100/27 km/hr

Distance = 300 km

Time taken = distance/speed

$t = \frac{300}{ \frac{100}{27} } = 27 \times 3 = 81 \: hours$

So, if Tahir starts at 03:00 PM on Monday, he will reach to point z at 12:00 AM on Thursday.